-60x^2-32x+48=0

Solution for -60x^2-32x+48=0 equation:

-60x^2-32x+48=0

a = -60; b = -32; c = +48;
Δ = b2-4ac
Δ = -322-4·(-60)·48
Δ = 12544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{12544}=112$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-112}{2*-60}=\frac{-80}{-120}
=2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+112}{2*-60}=\frac{144}{-120}
=-1+1/5
$